Prahu opines re the mathematics of love
Her equations hypotenuse me,
So I write adjacently,
As if we were cosine functionalities.
A special formula,
A Hyperbolic Cosine,
For to equate love mathematically,
We must use verbal hyperbole.
Binomials, the pair of loves,
Coefficient Trekkers,
On the mountains of waves,
To a product infinite.
So let us,
Reductio ad absurdum
That love is pointless.
Nah, nope.
Love is the point on a curve
that never stops moving,
Even as the curve forever, bending
And the possibilities,
Exponential...
In the sums of love,
The finite answer is always two.
So let us be clear,
This exercise has made me late
For work,
For which
I express my appreciation as follows:
X = xo,
Or
Summation Expansion
e e= 1 / n!
= 1/1 + 1/1 + 1/2 + 1/6 + ... see constant e
e -1 = (-1) n / n!
= 1/1 - 1/1 + 1/2 - 1/6 + ...
e x = xn / n!
= 1/1 + x/1 + x2 / 2 + x3 / 6 + ...
Sep 19, 2013
Sep 19, 2013 at 6:45 AM UTC
Prahu opines re the mathematics of love
Her equations hypotenuse me,
So I write adjacently,
As if we were cosine functionalities.
A special formula,
A Hyperbolic Cosine,
For to equate love mathematically,
We must use verbal hyperbole.
Binomials, the pair of loves,
Coefficient Trekkers,
On the mountains of waves,
To a product infinite.
So let us,
Reductio ad absurdum
That love is pointless.
Nah, nope.
Love is the point on a curve
that never stops moving,
Even as the curve forever, bending
And the possibilities,
Exponential...
In the sums of love,
The finite answer is always two.
So let us be clear,
This exercise has made me late
For work,
For which
I express my appreciation as follows:
X = xo,
Or
Summation Expansion
e e= 1 / n!
= 1/1 + 1/1 + 1/2 + 1/6 + ... see constant e
e -1 = (-1) n / n!
= 1/1 - 1/1 + 1/2 - 1/6 + ...
e x = xn / n!
= 1/1 + x/1 + x2 / 2 + x3 / 6 + ...
Prabhu Iyer · 3 hours ago
Singularity
My heart rate, sine wave usually, goes
sine squared when I see you,
sine cubed when I approach you,
woh, Dirac-delta when I hear you!
How do I heal this singularity?
Now how do I extract the real part
from your complex valued smile at me?
Euler says, it all goes in circles anyways.
So, I decide to cast a phasor P
that intersects the line H bisecting
your heart plane, such that H · P = 0.
Can Cupid tell dot product from cross?
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